$$\frac{1}{x-2}-\frac{1}{x-5}=\frac{1}{x3}-\frac{1}{x-6}$$
$x_{3}=-\frac{\left(2-x\right)\left(x-6\right)\left(x-5\right)}{x^{2}-10x+28}$
$x\neq 2\text{ and }x\neq 5\text{ and }x\neq 6$
