Question

$$\frac{1}{x+x+1}=\frac{A}{x}+\frac{B}{x+1}-$$

Answer

x=(Ax+Bx-)/2

Solution


Cancel \(1\) on both sides.
\[1\times x+x=Ax+Bx-\]
Simplify  \(1\times x\)  to  \(x\).
\[x+x=Ax+Bx-\]
Simplify  \(x+x\)  to  \(2x\).
\[2x=Ax+Bx-\]
Divide both sides by \(2\).
\[x=\frac{Ax+Bx-}{2}\]