Factor \({x}^{2}-7x+12\).
Ask: Which two numbers add up to \(-7\) and multiply to \(12\)?
Rewrite the expression using the above.
\[(x-4)(x-3)\]
\[\frac{1}{(x-4)(x-3)}+\frac{1}{x-3}\]
Rewrite the expression with a common denominator.
\[\frac{1+x-4}{(x-4)(x-3)}\]
Simplify \(1+x-4\) to \(x-3\).
\[\frac{x-3}{(x-4)(x-3)}\]
Cancel \(x-3\).
\[\frac{1}{x-4}\]
1/(x-4)
