Question

$$\frac{1-y}{y^{7}}; \frac{x-y^{\frac{2}{3}}}{7y-7}$$

Answer

$$-1/(y^7;(x-y^(2/3))*7)$$

Solution


Factor out the common term \(7\).
\[\begin{aligned}&\frac{1-y}{{y}^{7}}\\&\frac{x-{y}^{\frac{2}{3}}}{7(y-1)}\end{aligned}\]
Factor out the negative sign in \(1-y\).
\[\begin{aligned}&-\frac{-1+y}{{y}^{7}\\&(x-{y}^{\frac{2}{3}})\times 7(y-1)}\end{aligned}\]
Regroup terms.
\[\begin{aligned}&-\frac{y-1}{{y}^{7}\\&(x-{y}^{\frac{2}{3}})\times 7(y-1)}\end{aligned}\]
Cancel \(y-1\).
\[\begin{aligned}&-\frac{1}{{y}^{7}\\&(x-{y}^{\frac{2}{3}})\times 7}\end{aligned}\]