$$\frac { 1 + i } { ( 2 + i ) ^ { 2 } }$$
$\frac{7}{25}-\frac{1}{25}i=0.28-0.04i$
$$\frac{1+i}{3+4i}$$
$$\frac{\left(1+i\right)\left(3-4i\right)}{\left(3+4i\right)\left(3-4i\right)}$$
$$\frac{7-i}{25}$$
$$\frac{7}{25}-\frac{1}{25}i$$
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$\frac{7}{25} = 0.28$
$$Re(\frac{1+i}{3+4i})$$
$$Re(\frac{\left(1+i\right)\left(3-4i\right)}{\left(3+4i\right)\left(3-4i\right)})$$
$$Re(\frac{7-i}{25})$$
$$Re(\frac{7}{25}-\frac{1}{25}i)$$
$$\frac{7}{25}$$
