$$\frac{ 10 { A }^{ 2 } { B }^{ 3 } C }{ 80( { A }^{ 3 } - { A }^{ 2 } B) }$$
$\frac{CB^{3}}{8\left(A-B\right)}$
$$\frac{CA^{2}B^{3}}{8\left(A^{3}-BA^{2}\right)}$$
$$\frac{CA^{2}B^{3}}{8\left(A-B\right)A^{2}}$$
$$\frac{CB^{3}}{8\left(A-B\right)}$$
$$\frac{CB^{3}}{8A-8B}$$
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