$$\frac { 10 } { \frac { 3 } { 7 } } - \frac { 9 } { 2 } = \frac { 6 } { 2 } \frac { - 3 } { 2 }$$
$\text{false}$
$$10\times \frac{7}{3}-\frac{9}{2}=\frac{6}{2}\times \frac{-3}{2}$$
$$\frac{10\times 7}{3}-\frac{9}{2}=\frac{6}{2}\times \frac{-3}{2}$$
$$\frac{70}{3}-\frac{9}{2}=\frac{6}{2}\times \frac{-3}{2}$$
$$\frac{140}{6}-\frac{27}{6}=\frac{6}{2}\times \frac{-3}{2}$$
$$\frac{140-27}{6}=\frac{6}{2}\times \frac{-3}{2}$$
$$\frac{113}{6}=\frac{6}{2}\times \frac{-3}{2}$$
$$\frac{113}{6}=3\times \frac{-3}{2}$$
$$\frac{113}{6}=3\left(-\frac{3}{2}\right)$$
$$\frac{113}{6}=\frac{3\left(-3\right)}{2}$$
$$\frac{113}{6}=\frac{-9}{2}$$
$$\frac{113}{6}=-\frac{9}{2}$$
$$\frac{113}{6}=-\frac{27}{6}$$
$$\text{false}$$
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