$$\frac{10}{x+4}+\frac{2}{x-y}=4:\frac{15}{x+4}-\frac{5}{x-y}=2$$
$\frac{2\left(6x-5y+4\right)}{\left(x+4\right)\left(x-y\right)}=\frac{4x^{2}-4xy+16x-16y-75}{15\left(x-y\right)}\text{ and }\frac{4x^{2}-4xy+16x-16y-75}{15\left(x-y\right)}=2$
$\left\{\begin{matrix}x=\frac{5\sqrt{201}+73}{8}\text{, }&y=\frac{3\sqrt{201}+91}{8}\\x=\frac{73-5\sqrt{201}}{8}\text{, }&y=\frac{91-3\sqrt{201}}{8}\end{matrix}\right.$
$\left\{\begin{matrix}y=\frac{91-3\sqrt{201}}{8}\text{, }&x=\frac{73-5\sqrt{201}}{8}\\y=\frac{3\sqrt{201}+91}{8}\text{, }&x=\frac{5\sqrt{201}+73}{8}\end{matrix}\right.$
