$$\frac{10}{x+y}+\frac{2}{x-y}=4:\frac{15}{x+4}=\frac{5}{x-y}=2$$
$\frac{4\left(3x-2y\right)}{x^{2}-y^{2}}=\frac{4\left(x+4\right)}{15}\text{ and }\frac{4\left(x+4\right)}{15}=\frac{5}{x-y}\text{ and }\frac{5}{x-y}=2$
