$$\frac{10(y+12)-17(2-y)}{7y-1}=16$$
$y = \frac{6}{5} = 1\frac{1}{5} = 1.2$
$$10\left(y+12\right)-17\left(2-y\right)=16\left(7y-1\right)$$
$$10y+120-17\left(2-y\right)=16\left(7y-1\right)$$
$$10y+120-34+17y=16\left(7y-1\right)$$
$$10y+86+17y=16\left(7y-1\right)$$
$$27y+86=16\left(7y-1\right)$$
$$27y+86=112y-16$$
$$27y+86-112y=-16$$
$$-85y+86=-16$$
$$-85y=-16-86$$
$$-85y=-102$$
$$y=\frac{-102}{-85}$$
$$y=\frac{6}{5}$$
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