How to solve (10x)/(3-5x)=4

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (10x)/(3-5x)=4 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

$$\frac{ 10x }{ 3-5x } =4$$

$x=\frac{2}{5}=0.4$

Variable $x$ cannot be equal to $\frac{3}{5}$ since division by zero is not defined. Multiply both sides of the equation by $-5x+3$.

$$10x=4\left(-5x+3\right)$$

Use the distributive property to multiply $4$ by $-5x+3$.

$$10x=-20x+12$$

Add $20x$ to both sides.

$$10x+20x=12$$

Combine $10x$ and $20x$ to get $30x$.

$$30x=12$$

Divide both sides by $30$.

$$x=\frac{12}{30}$$

Reduce the fraction $\frac{12}{30}$ to lowest terms by extracting and canceling out $6$.

$$x=\frac{2}{5}$$