$$\frac{116-3}{9}+\frac{3x-4}{9}=0.$$
$x = -\frac{109}{3} = -36\frac{1}{3} \approx -36.333333333$
$$116-3+3x-4=0$$
$$113+3x-4=0$$
$$109+3x=0$$
$$3x=-109$$
$$x=\frac{-109}{3}$$
$$x=-\frac{109}{3}$$
Show Solution
Hide Solution