How to solve 12/15 - 7/15

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 12/15 - 7/15 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

$$\frac{12}{15}-\frac{7}{15}$$

$\frac{1}{3}\approx 0.333333333$

Since $\frac{12}{15}$ and $\frac{7}{15}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{12-7}{15}$$

Subtract $7$ from $12$ to get $5$.

$$\frac{5}{15}$$

Reduce the fraction $\frac{5}{15}$ to lowest terms by extracting and canceling out $5$.

$$\frac{1}{3}$$

$\frac{1}{3} = 0.3333333333333333$