$$\frac{ 121 }{ 11+55+2 \times 3- \frac{ 28 }{ 4 } }$$
$\frac{121}{65}\approx 1.861538462$
$$\frac{121}{66+2\times 3-\frac{28}{4}}$$
$$\frac{121}{66+6-\frac{28}{4}}$$
$$\frac{121}{72-\frac{28}{4}}$$
$$\frac{121}{72-7}$$
$$\frac{121}{65}$$
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$\frac{11 ^ {2}}{5 \cdot 13} = 1\frac{56}{65} = 1.8615384615384616$
