How to solve 121/39 / (11/6)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 121/39 / (11/6) | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

$$\frac{121}{39}\div\frac{11}{6}$$

$\frac{22}{13}\approx 1.692307692$

Divide $\frac{121}{39}$ by $\frac{11}{6}$ by multiplying $\frac{121}{39}$ by the reciprocal of $\frac{11}{6}$.

$$\frac{121}{39}\times \frac{6}{11}$$

Multiply $\frac{121}{39}$ times $\frac{6}{11}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{121\times 6}{39\times 11}$$

Do the multiplications in the fraction $\frac{121\times 6}{39\times 11}$.

$$\frac{726}{429}$$

Reduce the fraction $\frac{726}{429}$ to lowest terms by extracting and canceling out $33$.

$$\frac{22}{13}$$

$\frac{2 \cdot 11}{13} = 1\frac{9}{13} = 1.6923076923076923$