$$\frac{13}{1+i}$$
$\frac{13}{2}-\frac{13}{2}i=6.5-6.5i$
$$\frac{13\left(1-i\right)}{\left(1+i\right)\left(1-i\right)}$$
$$\frac{13\left(1-i\right)}{1^{2}-i^{2}}$$
$$\frac{13\left(1-i\right)}{2}$$
$$\frac{13\times 1+13\left(-i\right)}{2}$$
$$\frac{13-13i}{2}$$
$$\frac{13}{2}-\frac{13}{2}i$$
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$\frac{13}{2} = 6\frac{1}{2} = 6.5$
$$Re(\frac{13\left(1-i\right)}{\left(1+i\right)\left(1-i\right)})$$
$$Re(\frac{13\left(1-i\right)}{1^{2}-i^{2}})$$
$$Re(\frac{13\left(1-i\right)}{2})$$
$$Re(\frac{13\times 1+13\left(-i\right)}{2})$$
$$Re(\frac{13-13i}{2})$$
$$Re(\frac{13}{2}-\frac{13}{2}i)$$
$$\frac{13}{2}$$
