How to solve (14)/(3)+y=3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (14)/(3)+y=3 | Equatix

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$$\frac{ 14 }{ 3 } +y=3$$

$y = -\frac{5}{3} = -1\frac{2}{3} \approx -1.666666667$

Subtract $\frac{14}{3}$ from both sides.

$$y=3-\frac{14}{3}$$

Convert $3$ to fraction $\frac{9}{3}$.

$$y=\frac{9}{3}-\frac{14}{3}$$

Since $\frac{9}{3}$ and $\frac{14}{3}$ have the same denominator, subtract them by subtracting their numerators.

$$y=\frac{9-14}{3}$$

Subtract $14$ from $9$ to get $-5$.

$$y=-\frac{5}{3}$$