How to solve 15/12 - i/3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 15/12 - i/3 | Equatix

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$$\frac{15}{12}-\frac{i}{3}$$

$\frac{5}{4}-\frac{1}{3}i\approx 1.25-0.333333333i$

$\frac{5}{4} = 1\frac{1}{4} = 1.25$

Reduce the fraction $\frac{15}{12}$ to lowest terms by extracting and canceling out $3$.

$$Re(\frac{5}{4}-\frac{i}{3})$$

Divide $i$ by $3$ to get $\frac{1}{3}i$.

$$Re(\frac{5}{4}-\frac{1}{3}i)$$

The real part of $\frac{5}{4}-\frac{1}{3}i$ is $\frac{5}{4}$.

$$\frac{5}{4}$$