How to solve (15)/(6)+(4)/(9)=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (15)/(6)+(4)/(9)= | Equatix

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$$\frac{ 15 }{ 6 } + \frac{ 4 }{ 9 } =$$

$\frac{53}{18}\approx 2.944444444$

Reduce the fraction $\frac{15}{6}$ to lowest terms by extracting and canceling out $3$.

$$\frac{5}{2}+\frac{4}{9}$$

Least common multiple of $2$ and $9$ is $18$. Convert $\frac{5}{2}$ and $\frac{4}{9}$ to fractions with denominator $18$.

$$\frac{45}{18}+\frac{8}{18}$$

Since $\frac{45}{18}$ and $\frac{8}{18}$ have the same denominator, add them by adding their numerators.

$$\frac{45+8}{18}$$

Add $45$ and $8$ to get $53$.

$$\frac{53}{18}$$

$\frac{53}{2 \cdot 3 ^ {2}} = 2\frac{17}{18} = 2.9444444444444446$