How to solve 15/8 + 21/10 =

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 15/8 + 21/10 = | Equatix

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$$\frac{15}{8}+\frac{21}{10}=$$

$\frac{159}{40}=3.975$

Least common multiple of $8$ and $10$ is $40$. Convert $\frac{15}{8}$ and $\frac{21}{10}$ to fractions with denominator $40$.

$$\frac{75}{40}+\frac{84}{40}$$

Since $\frac{75}{40}$ and $\frac{84}{40}$ have the same denominator, add them by adding their numerators.

$$\frac{75+84}{40}$$

Add $75$ and $84$ to get $159$.

$$\frac{159}{40}$$

$\frac{3 \cdot 53}{2 ^ {3} \cdot 5} = 3\frac{39}{40} = 3.975$