How to solve 15/9 + 24/4 - 6/8

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 15/9 + 24/4 - 6/8 | Equatix

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Question

$$\frac{15}{9}+\frac{24}{4}-\frac{6}{8}$$

Evaluate

$\frac{83}{12}\approx 6.916666667$

Solution Steps

Reduce the fraction $\frac{15}{9}$ to lowest terms by extracting and canceling out $3$.

$$\frac{5}{3}+\frac{24}{4}-\frac{6}{8}$$

Divide $24$ by $4$ to get $6$.

$$\frac{5}{3}+6-\frac{6}{8}$$

Convert $6$ to fraction $\frac{18}{3}$.

$$\frac{5}{3}+\frac{18}{3}-\frac{6}{8}$$

Since $\frac{5}{3}$ and $\frac{18}{3}$ have the same denominator, add them by adding their numerators.

$$\frac{5+18}{3}-\frac{6}{8}$$

Add $5$ and $18$ to get $23$.

$$\frac{23}{3}-\frac{6}{8}$$

Reduce the fraction $\frac{6}{8}$ to lowest terms by extracting and canceling out $2$.

$$\frac{23}{3}-\frac{3}{4}$$

Least common multiple of $3$ and $4$ is $12$. Convert $\frac{23}{3}$ and $\frac{3}{4}$ to fractions with denominator $12$.

$$\frac{92}{12}-\frac{9}{12}$$

Since $\frac{92}{12}$ and $\frac{9}{12}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{92-9}{12}$$

Subtract $9$ from $92$ to get $83$.

$$\frac{83}{12}$$

Show Solution

Factor

$\frac{83}{2 ^ {2} \cdot 3} = 6\frac{11}{12} = 6.916666666666667$