Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$\frac{15m_{x=0}1-\cos\ x\ \cos\ 2x-\cos\ 3x}{x^{2}}$$

Answer

$$m=(1-cos(x)*cos(2*x)-x^2*cos(3*x))/(15*x)$$

Solution


Regroup terms.
\[15mx=01-\cos{x}\cos{2x}-{x}^{2}\cos{3x}\]
Simplify  \(01-\cos{x}\cos{2x}-{x}^{2}\cos{3x}\)  to  \(1-\cos{x}\cos{2x}-{x}^{2}\cos{3x}\).
\[15mx=1-\cos{x}\cos{2x}-{x}^{2}\cos{3x}\]
Divide both sides by \(15\).
\[mx=\frac{1-\cos{x}\cos{2x}-{x}^{2}\cos{3x}}{15}\]
Divide both sides by \(x\).
\[m=\frac{\frac{1-\cos{x}\cos{2x}-{x}^{2}\cos{3x}}{15}}{x}\]
Simplify  \(\frac{\frac{1-\cos{x}\cos{2x}-{x}^{2}\cos{3x}}{15}}{x}\)  to  \(\frac{1-\cos{x}\cos{2x}-{x}^{2}\cos{3x}}{15x}\).
\[m=\frac{1-\cos{x}\cos{2x}-{x}^{2}\cos{3x}}{15x}\]
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