$$\frac { 16 a ^ { 2 } b ^ { 2 } } { 12 a ^ { 2 } b ^ { 3 } + 20 a ^ { 3 } b ^ { 2 } }$$
$\frac{4}{5a+3b}$
$$\frac{16a^{2}b^{2}}{4\left(5a+3b\right)a^{2}b^{2}}$$
$$\frac{4}{5a+3b}$$
Show Solution
Hide Solution
$-\frac{12}{\left(5a+3b\right)^{2}}$
