How to solve 17/10 - 14/27

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 17/10 - 14/27 | Equatix

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$$\frac{17}{10}-\frac{14}{27}$$

$\frac{319}{270}\approx 1.181481481$

Least common multiple of $10$ and $27$ is $270$. Convert $\frac{17}{10}$ and $\frac{14}{27}$ to fractions with denominator $270$.

$$\frac{459}{270}-\frac{140}{270}$$

Since $\frac{459}{270}$ and $\frac{140}{270}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{459-140}{270}$$

Subtract $140$ from $459$ to get $319$.

$$\frac{319}{270}$$

$\frac{11 \cdot 29}{2 \cdot 3 ^ {3} \cdot 5} = 1\frac{49}{270} = 1.1814814814814816$