Question

$$\frac{ 18 { \times }^{ 5 } { y }^{ 5 } }{ -6 \times { y }^{ 2 } }$$

Answer

$$-3*^6*y^3$$

Solution


Remove parentheses.
\[\frac{18{}^{5}{y}^{5}}{-6{y}^{2}}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\frac{18{}^{6}{y}^{5}}{-6{y}^{2}}\]
Move the negative sign to the left.
\[-\frac{18{}^{6}{y}^{5}}{6{y}^{2}}\]
Take out the constants.
\[-\frac{18}{6}\times \frac{{}^{6}{y}^{5}}{{y}^{2}}\]
Simplify  \(\frac{18}{6}\)  to  \(3\).
\[-3\times \frac{{}^{6}{y}^{5}}{{y}^{2}}\]
Simplify  \(3\times \frac{{}^{6}{y}^{5}}{{y}^{2}}\)  to  \(3{}^{6}{y}^{3}\).
\[-3{}^{6}{y}^{3}\]