$$\frac { 18 } { 11 } \times \frac { - 33 } { 45 }$$
$-\frac{6}{5}=-1.2$
$$\frac{18}{11}\left(-\frac{11}{15}\right)$$
$$\frac{18\left(-11\right)}{11\times 15}$$
$$\frac{-198}{165}$$
$$-\frac{6}{5}$$
Show Solution
Hide Solution
$-\frac{6}{5} = -1\frac{1}{5} = -1.2$