$$\frac{18}{3\sqrt{2}-2\sqrt{3}}$$
$6\sqrt{3}+9\sqrt{2}\approx 23.120226907$
$$\frac{18\left(3\sqrt{2}+2\sqrt{3}\right)}{\left(3\sqrt{2}-2\sqrt{3}\right)\left(3\sqrt{2}+2\sqrt{3}\right)}$$
$$\frac{18\left(3\sqrt{2}+2\sqrt{3}\right)}{\left(3\sqrt{2}\right)^{2}-\left(-2\sqrt{3}\right)^{2}}$$
$$\frac{18\left(3\sqrt{2}+2\sqrt{3}\right)}{3^{2}\left(\sqrt{2}\right)^{2}-\left(-2\sqrt{3}\right)^{2}}$$
$$\frac{18\left(3\sqrt{2}+2\sqrt{3}\right)}{9\left(\sqrt{2}\right)^{2}-\left(-2\sqrt{3}\right)^{2}}$$
$$\frac{18\left(3\sqrt{2}+2\sqrt{3}\right)}{9\times 2-\left(-2\sqrt{3}\right)^{2}}$$
$$\frac{18\left(3\sqrt{2}+2\sqrt{3}\right)}{18-\left(-2\sqrt{3}\right)^{2}}$$
$$\frac{18\left(3\sqrt{2}+2\sqrt{3}\right)}{18-\left(-2\right)^{2}\left(\sqrt{3}\right)^{2}}$$
$$\frac{18\left(3\sqrt{2}+2\sqrt{3}\right)}{18-4\left(\sqrt{3}\right)^{2}}$$
$$\frac{18\left(3\sqrt{2}+2\sqrt{3}\right)}{18-4\times 3}$$
$$\frac{18\left(3\sqrt{2}+2\sqrt{3}\right)}{18-12}$$
$$\frac{18\left(3\sqrt{2}+2\sqrt{3}\right)}{6}$$
$$3\left(3\sqrt{2}+2\sqrt{3}\right)$$
$$9\sqrt{2}+6\sqrt{3}$$
Show Solution
Hide Solution