$$\frac{18a^{3}b-12a^{2}b^{2}}{-3ab}$$
$-2a\left(3a-2b\right)$
$$\frac{6b\left(3a-2b\right)a^{2}}{-3ab}$$
$$\frac{2a\left(3a-2b\right)}{-1}$$
$$-6a^{2}+4ab$$
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$4ab-6a^{2}$
