Question

$$\frac{ 2 { \times }^{ 2-5 } }{ x } = \frac{ 2(1)-5 }{ 1 }$$

Answer

x=-1/3

Solution


Remove parentheses.
\[\frac{2{}^{2-5}}{x}=\frac{2\times 1-5}{1}\]
Simplify  \(2-5\)  to  \(-3\).
\[\frac{2{}^{-3}}{x}=\frac{2\times 1-5}{1}\]
Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[\frac{2\times \frac{1}{{}^{3}}}{x}=\frac{2\times 1-5}{1}\]
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[\frac{\frac{2\times 1}{{}^{3}}}{x}=\frac{2\times 1-5}{1}\]
Simplify  \(2\times 1\)  to  \(2\).
\[\frac{\frac{2}{{}^{3}}}{x}=\frac{2\times 1-5}{1}\]
Simplify  \(\frac{2}{{}^{3}}\)  to  \(\frac{2}{{}^{2}}\).
\[\frac{\frac{2}{{}^{2}}}{x}=\frac{2\times 1-5}{1}\]
Simplify  \(2\times 1\)  to  \(2\).
\[\frac{\frac{2}{{}^{2}}}{x}=\frac{2-5}{1}\]
Simplify  \(2-5\)  to  \(-3\).
\[\frac{\frac{2}{{}^{2}}}{x}=\frac{-3}{1}\]
Simplify  \(\frac{\frac{2}{{}^{2}}}{x}\)  to  \(\frac{2}{{}^{2}x}\).
\[\frac{2}{{}^{2}x}=\frac{-3}{1}\]
Simplify  \(\frac{-3}{1}\)  to  \(-3\).
\[\frac{2}{{}^{2}x}=-3\]
Multiply both sides by \({}^{2}x\).
\[2=-3{}^{2}x\]
Divide both sides by \(-3\).
\[-\frac{2}{3}=2x\]
Divide both sides by \(2\).
\[-\frac{\frac{2}{3}}{2}=x\]
Simplify  \(\frac{\frac{2}{3}}{2}\)  to  \(\frac{2}{3\times 2}\).
\[-\frac{2}{3\times 2}=x\]
Simplify  \(3\times 2\)  to  \(6\).
\[-\frac{2}{6}=x\]
Simplify  \(\frac{2}{6}\)  to  \(\frac{1}{3}\).
\[-\frac{1}{3}=x\]
Switch sides.
\[x=-\frac{1}{3}\]

Decimal Form: -0.333333