1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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Question

$$\frac { 2 } { 10 } + \frac { 1 } { 20 } + \frac { 1 } { 10 }$$

Evaluate

$\frac{7}{20}=0.35$

Solution Steps

Reduce the fraction $\frac{2}{10}$ to lowest terms by extracting and canceling out $2$.

$$\frac{1}{5}+\frac{1}{20}+\frac{1}{10}$$

Least common multiple of $5$ and $20$ is $20$. Convert $\frac{1}{5}$ and $\frac{1}{20}$ to fractions with denominator $20$.

$$\frac{4}{20}+\frac{1}{20}+\frac{1}{10}$$

Since $\frac{4}{20}$ and $\frac{1}{20}$ have the same denominator, add them by adding their numerators.

$$\frac{4+1}{20}+\frac{1}{10}$$

Add $4$ and $1$ to get $5$.

$$\frac{5}{20}+\frac{1}{10}$$

Reduce the fraction $\frac{5}{20}$ to lowest terms by extracting and canceling out $5$.

$$\frac{1}{4}+\frac{1}{10}$$

Least common multiple of $4$ and $10$ is $20$. Convert $\frac{1}{4}$ and $\frac{1}{10}$ to fractions with denominator $20$.

$$\frac{5}{20}+\frac{2}{20}$$

Since $\frac{5}{20}$ and $\frac{2}{20}$ have the same denominator, add them by adding their numerators.

$$\frac{5+2}{20}$$

Add $5$ and $2$ to get $7$.

$$\frac{7}{20}$$

Show Solution

Factor

$\frac{7}{2 ^ {2} \cdot 5} = 0.35$