$$\frac { 2 } { 2 } = \frac { \frac { 8 } { 3 } } { \frac { - \frac { 1 } { 2 } } { 6 } }$$
$\text{false}$
$$1=\frac{\frac{8}{3}}{\frac{-\frac{1}{2}}{6}}$$
$$1=\frac{8\times 6}{3\left(-\frac{1}{2}\right)}$$
$$1=\frac{2\times 8}{-\frac{1}{2}}$$
$$1=\frac{16}{-\frac{1}{2}}$$
$$1=16\left(-2\right)$$
$$1=-32$$
$$\text{false}$$
Show Solution
Hide Solution
