$$\frac { 2 } { 3 } [ 6 + \{ 4 + 10 - 2 \} \times 4 ]$$
$36$
$$\frac{2}{3}\left(6+\left(14-2\right)\times 4\right)$$
$$\frac{2}{3}\left(6+12\times 4\right)$$
$$\frac{2}{3}\left(6+48\right)$$
$$\frac{2}{3}\times 54$$
$$\frac{2\times 54}{3}$$
$$\frac{108}{3}$$
$$36$$
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$2^{2}\times 3^{2}$