How to solve 2/3 - 6/8

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2/3 - 6/8 | Equatix

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$$\frac{2}{3}-\frac{6}{8}$$

$-\frac{1}{12}\approx -0.083333333$

Reduce the fraction $\frac{6}{8}$ to lowest terms by extracting and canceling out $2$.

$$\frac{2}{3}-\frac{3}{4}$$

Least common multiple of $3$ and $4$ is $12$. Convert $\frac{2}{3}$ and $\frac{3}{4}$ to fractions with denominator $12$.

$$\frac{8}{12}-\frac{9}{12}$$

Since $\frac{8}{12}$ and $\frac{9}{12}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{8-9}{12}$$

Subtract $9$ from $8$ to get $-1$.

$$-\frac{1}{12}$$

$-\frac{1}{12} = -0.08333333333333333$