$$\frac { 2 } { 3 } ( 5 x - 2 ) - ( 4 x - \frac { 1 - 3 x } { 2 } ) = \frac { 5 x - 11 } { 2 }$$
$x=1$
$$4\left(5x-2\right)-6\left(4x-\frac{1-3x}{2}\right)=3\left(5x-11\right)$$
$$20x-8-6\left(4x-\frac{1-3x}{2}\right)=3\left(5x-11\right)$$
$$20x-8-6\left(4x-\frac{1-3x}{2}\right)=15x-33$$
$$20x-8-6\left(4x-\left(\frac{1}{2}-\frac{3}{2}x\right)\right)=15x-33$$
$$20x-8-6\left(4x-\frac{1}{2}-\left(-\frac{3}{2}x\right)\right)=15x-33$$
$$20x-8-6\left(4x-\frac{1}{2}+\frac{3}{2}x\right)=15x-33$$
$$20x-8-6\left(\frac{11}{2}x-\frac{1}{2}\right)=15x-33$$
$$20x-8-6\times \frac{11}{2}x-6\left(-\frac{1}{2}\right)=15x-33$$
$$20x-8+\frac{-6\times 11}{2}x-6\left(-\frac{1}{2}\right)=15x-33$$
$$20x-8+\frac{-66}{2}x-6\left(-\frac{1}{2}\right)=15x-33$$
$$20x-8-33x-6\left(-\frac{1}{2}\right)=15x-33$$
$$20x-8-33x+\frac{-6\left(-1\right)}{2}=15x-33$$
$$20x-8-33x+\frac{6}{2}=15x-33$$
$$20x-8-33x+3=15x-33$$
$$-13x-8+3=15x-33$$
$$-13x-5=15x-33$$
$$-13x-5-15x=-33$$
$$-28x-5=-33$$
$$-28x=-33+5$$
$$-28x=-28$$
$$x=\frac{-28}{-28}$$
$$x=1$$
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