$$\frac{ 2 }{ 3 } (x+2) < \frac{ 1 }{ 4 } x+3$$
$x<4$
$$\frac{2}{3}x+\frac{2}{3}\times 2<\frac{1}{4}x+3$$
$$\frac{2}{3}x+\frac{2\times 2}{3}<\frac{1}{4}x+3$$
$$\frac{2}{3}x+\frac{4}{3}<\frac{1}{4}x+3$$
$$\frac{2}{3}x+\frac{4}{3}-\frac{1}{4}x<3$$
$$\frac{5}{12}x+\frac{4}{3}<3$$
$$\frac{5}{12}x<3-\frac{4}{3}$$
$$\frac{5}{12}x<\frac{9}{3}-\frac{4}{3}$$
$$\frac{5}{12}x<\frac{9-4}{3}$$
$$\frac{5}{12}x<\frac{5}{3}$$
$$x<\frac{5}{3}\times \frac{12}{5}$$
$$x<\frac{5\times 12}{3\times 5}$$
$$x<\frac{12}{3}$$
$$x<4$$
Show Solution
Hide Solution
