How to solve 2/3 + 1 - 1/6 =

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2/3 + 1 - 1/6 = | Equatix

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Question

$$\frac{2}{3}+1-\frac{1}{6}=$$

Evaluate

$\frac{3}{2}=1.5$

Solution Steps

Convert $1$ to fraction $\frac{3}{3}$.

$$\frac{2}{3}+\frac{3}{3}-\frac{1}{6}$$

Since $\frac{2}{3}$ and $\frac{3}{3}$ have the same denominator, add them by adding their numerators.

$$\frac{2+3}{3}-\frac{1}{6}$$

Add $2$ and $3$ to get $5$.

$$\frac{5}{3}-\frac{1}{6}$$

Least common multiple of $3$ and $6$ is $6$. Convert $\frac{5}{3}$ and $\frac{1}{6}$ to fractions with denominator $6$.

$$\frac{10}{6}-\frac{1}{6}$$

Since $\frac{10}{6}$ and $\frac{1}{6}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{10-1}{6}$$

Subtract $1$ from $10$ to get $9$.

$$\frac{9}{6}$$

Reduce the fraction $\frac{9}{6}$ to lowest terms by extracting and canceling out $3$.

$$\frac{3}{2}$$

Show Solution

Factor

$\frac{3}{2} = 1\frac{1}{2} = 1.5$