1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6 + 3 | Equatix

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Question

$$\frac { 2 } { 3 } + \frac { 4 } { 5 } + \frac { 1 } { 9 }$$

$\frac{71}{45}\approx 1.577777778$

Least common multiple of $3$ and $5$ is $15$. Convert $\frac{2}{3}$ and $\frac{4}{5}$ to fractions with denominator $15$.

$$\frac{10}{15}+\frac{12}{15}+\frac{1}{9}$$

Since $\frac{10}{15}$ and $\frac{12}{15}$ have the same denominator, add them by adding their numerators.

$$\frac{10+12}{15}+\frac{1}{9}$$

Add $10$ and $12$ to get $22$.

$$\frac{22}{15}+\frac{1}{9}$$

Least common multiple of $15$ and $9$ is $45$. Convert $\frac{22}{15}$ and $\frac{1}{9}$ to fractions with denominator $45$.

$$\frac{66}{45}+\frac{5}{45}$$

Since $\frac{66}{45}$ and $\frac{5}{45}$ have the same denominator, add them by adding their numerators.

$$\frac{66+5}{45}$$

Add $66$ and $5$ to get $71$.

$$\frac{71}{45}$$

$\frac{71}{3 ^ {2} \cdot 5} = 1\frac{26}{45} = 1.5777777777777777$