$$\frac { 2 } { 3 } x - 1 + \frac { 3 } { 3 } x + 1 = \frac { 5 } { 9 } x$$
$x=0$
$$\frac{2}{3}x-1+1x+1=\frac{5}{9}x$$
$$\frac{5}{3}x-1+1=\frac{5}{9}x$$
$$\frac{5}{3}x=\frac{5}{9}x$$
$$\frac{5}{3}x-\frac{5}{9}x=0$$
$$\frac{10}{9}x=0$$
$$x=0$$
Show Solution
Hide Solution