$$\frac { 2 } { 3 } x + \frac { 1 } { 3 } x ^ { 2 } - \frac { 1 } { 5 } x + \frac { 1 } { 8 } x + \frac { 7 } { 3 } x ^ { 2 } + 3$$
$\frac{8x^{2}}{3}+\frac{71x}{120}+3$
$$\frac{7}{15}x+\frac{1}{3}x^{2}+\frac{1}{8}x+\frac{7}{3}x^{2}+3$$
$$\frac{71}{120}x+\frac{1}{3}x^{2}+\frac{7}{3}x^{2}+3$$
$$\frac{71}{120}x+\frac{8}{3}x^{2}+3$$
Show Solution
Hide Solution
$\frac{320x^{2}+71x+360}{120}$
$$\frac{80x+40x^{2}-24x+15x+280x^{2}+360}{120}$$
