$$\frac{2}{3y-3}=\frac{3}{9y-5}$$
$y=\frac{1}{9}\approx 0.111111111$
$$\left(9y-5\right)\times 2=\left(3y-3\right)\times 3$$
$$18y-10=\left(3y-3\right)\times 3$$
$$18y-10=9y-9$$
$$18y-10-9y=-9$$
$$9y-10=-9$$
$$9y=-9+10$$
$$9y=1$$
$$y=\frac{1}{9}$$
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