$$\frac{ 2 }{ 5 } \times \frac{ 5 }{ 3 } \times [8-(3+5)]$$
$0$
$$\frac{2\times 5}{5\times 3}\left(8-\left(3+5\right)\right)$$
$$\frac{2}{3}\left(8-\left(3+5\right)\right)$$
$$\frac{2}{3}\left(8-8\right)$$
$$\frac{2}{3}\times 0$$
$$0$$
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