How to solve 2/5 / (9/5) + 7/6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2/5 / (9/5) + 7/6 | Equatix

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$$\frac{2}{5}\div\frac{9}{5}+\frac{7}{6}$$

$\frac{25}{18}\approx 1.388888889$

Divide $\frac{2}{5}$ by $\frac{9}{5}$ by multiplying $\frac{2}{5}$ by the reciprocal of $\frac{9}{5}$.

$$\frac{2}{5}\times \frac{5}{9}+\frac{7}{6}$$

Multiply $\frac{2}{5}$ times $\frac{5}{9}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{2\times 5}{5\times 9}+\frac{7}{6}$$

Cancel out $5$ in both numerator and denominator.

$$\frac{2}{9}+\frac{7}{6}$$

Least common multiple of $9$ and $6$ is $18$. Convert $\frac{2}{9}$ and $\frac{7}{6}$ to fractions with denominator $18$.

$$\frac{4}{18}+\frac{21}{18}$$

Since $\frac{4}{18}$ and $\frac{21}{18}$ have the same denominator, add them by adding their numerators.

$$\frac{4+21}{18}$$

Add $4$ and $21$ to get $25$.

$$\frac{25}{18}$$

$\frac{5 ^ {2}}{2 \cdot 3 ^ {2}} = 1\frac{7}{18} = 1.3888888888888888$