$$\frac{2}{5}p+\frac{1}{3}=q+6$$
$p=\frac{5q}{2}+\frac{85}{6}$
$$\frac{2}{5}p=q+6-\frac{1}{3}$$
$$\frac{2}{5}p=q+\frac{17}{3}$$
$$\frac{\frac{2}{5}p}{\frac{2}{5}}=\frac{q+\frac{17}{3}}{\frac{2}{5}}$$
$$p=\frac{q+\frac{17}{3}}{\frac{2}{5}}$$
$$p=\frac{5q}{2}+\frac{85}{6}$$
Show Solution
Hide Solution
$q=\frac{2p}{5}-\frac{17}{3}$
$$q+6=\frac{2}{5}p+\frac{1}{3}$$
$$q=\frac{2}{5}p+\frac{1}{3}-6$$
$$q=\frac{2}{5}p-\frac{17}{3}$$
