$$\frac{2}{5}p+\frac{1}{3}=q+b$$
$b=\frac{2p}{5}-q+\frac{1}{3}$
$$q+b=\frac{2}{5}p+\frac{1}{3}$$
$$b=\frac{2}{5}p+\frac{1}{3}-q$$
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$p=\frac{5b}{2}+\frac{5q}{2}-\frac{5}{6}$
$$\frac{2}{5}p=q+b-\frac{1}{3}$$
$$\frac{\frac{2}{5}p}{\frac{2}{5}}=\frac{q+b-\frac{1}{3}}{\frac{2}{5}}$$
$$p=\frac{q+b-\frac{1}{3}}{\frac{2}{5}}$$
$$p=\frac{5b}{2}+\frac{5q}{2}-\frac{5}{6}$$
