How to solve (2)/(7)+4(4)/(15)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (2)/(7)+4(4)/(15) | Equatix

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$$\frac{ 2 }{ 7 } +4 \frac{ 4 }{ 15 }$$

$\frac{478}{105}\approx 4.552380952$

Multiply $4$ and $15$ to get $60$.

$$\frac{2}{7}+\frac{60+4}{15}$$

Add $60$ and $4$ to get $64$.

$$\frac{2}{7}+\frac{64}{15}$$

Least common multiple of $7$ and $15$ is $105$. Convert $\frac{2}{7}$ and $\frac{64}{15}$ to fractions with denominator $105$.

$$\frac{30}{105}+\frac{448}{105}$$

Since $\frac{30}{105}$ and $\frac{448}{105}$ have the same denominator, add them by adding their numerators.

$$\frac{30+448}{105}$$

Add $30$ and $448$ to get $478$.

$$\frac{478}{105}$$

$\frac{2 \cdot 239}{3 \cdot 5 \cdot 7} = 4\frac{58}{105} = 4.552380952380952$