How to solve 2/7 + 1/6 =

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2/7 + 1/6 = | Equatix

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$$\frac{2}{7}+\frac{1}{6}=$$

$\frac{19}{42}\approx 0.452380952$

Least common multiple of $7$ and $6$ is $42$. Convert $\frac{2}{7}$ and $\frac{1}{6}$ to fractions with denominator $42$.

$$\frac{12}{42}+\frac{7}{42}$$

Since $\frac{12}{42}$ and $\frac{7}{42}$ have the same denominator, add them by adding their numerators.

$$\frac{12+7}{42}$$

Add $12$ and $7$ to get $19$.

$$\frac{19}{42}$$

$\frac{19}{2 \cdot 3 \cdot 7} = 0.4523809523809524$