1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 12 ... | Equatix

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Question

$$\frac { 2 } { 8 } + \frac { 1 } { 12 }$$

$\frac{1}{3}\approx 0.333333333$

Reduce the fraction $\frac{2}{8}$ to lowest terms by extracting and canceling out $2$.

$$\frac{1}{4}+\frac{1}{12}$$

Least common multiple of $4$ and $12$ is $12$. Convert $\frac{1}{4}$ and $\frac{1}{12}$ to fractions with denominator $12$.

$$\frac{3}{12}+\frac{1}{12}$$

Since $\frac{3}{12}$ and $\frac{1}{12}$ have the same denominator, add them by adding their numerators.

$$\frac{3+1}{12}$$

Add $3$ and $1$ to get $4$.

$$\frac{4}{12}$$

Reduce the fraction $\frac{4}{12}$ to lowest terms by extracting and canceling out $4$.

$$\frac{1}{3}$$

$\frac{1}{3} = 0.3333333333333333$