Solve (2)/(8)+(1)/(4)=(1)/(2)-z | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\frac{ 2 }{ 8 } + \frac{ 1 }{ 4 } = \frac{ 1 }{ 2 } -z$$

Solve for z

$z=0$

Steps for Solving Linear Equation

Reduce the fraction $\frac{2}{8}$ to lowest terms by extracting and canceling out $2$.

$$\frac{1}{4}+\frac{1}{4}=\frac{1}{2}-z$$

Since $\frac{1}{4}$ and $\frac{1}{4}$ have the same denominator, add them by adding their numerators.

$$\frac{1+1}{4}=\frac{1}{2}-z$$

Add $1$ and $1$ to get $2$.

$$\frac{2}{4}=\frac{1}{2}-z$$

Reduce the fraction $\frac{2}{4}$ to lowest terms by extracting and canceling out $2$.

$$\frac{1}{2}=\frac{1}{2}-z$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{2}-z=\frac{1}{2}$$

Subtract $\frac{1}{2}$ from both sides.

$$-z=\frac{1}{2}-\frac{1}{2}$$

Subtract $\frac{1}{2}$ from $\frac{1}{2}$ to get $0$.

$$-z=0$$

Product of two numbers is equal to $0$ if at least one of them is $0$. Since $-1$ is not equal to $0$, $z$ must be equal to $0$.

$$z=0$$