1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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Question

$$\frac { 2 } { 8 } + \frac { - 2 } { 6 } =$$

$-\frac{1}{12}\approx -0.083333333$

Reduce the fraction $\frac{2}{8}$ to lowest terms by extracting and canceling out $2$.

$$\frac{1}{4}+\frac{-2}{6}$$

Reduce the fraction $\frac{-2}{6}$ to lowest terms by extracting and canceling out $2$.

$$\frac{1}{4}-\frac{1}{3}$$

Least common multiple of $4$ and $3$ is $12$. Convert $\frac{1}{4}$ and $\frac{1}{3}$ to fractions with denominator $12$.

$$\frac{3}{12}-\frac{4}{12}$$

Since $\frac{3}{12}$ and $\frac{4}{12}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-4}{12}$$

Subtract $4$ from $3$ to get $-1$.

$$-\frac{1}{12}$$

$-\frac{1}{12} = -0.08333333333333333$