How to solve 2/9 * 3/5 * 7/3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2/9 * 3/5 * 7/3 | Equatix

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$$\frac{2}{9}\times\frac{3}{5}\times\frac{7}{3}$$

$\frac{14}{45}\approx 0.311111111$

Multiply $\frac{2}{9}$ times $\frac{3}{5}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{2\times 3}{9\times 5}\times \frac{7}{3}$$

Do the multiplications in the fraction $\frac{2\times 3}{9\times 5}$.

$$\frac{6}{45}\times \frac{7}{3}$$

Reduce the fraction $\frac{6}{45}$ to lowest terms by extracting and canceling out $3$.

$$\frac{2}{15}\times \frac{7}{3}$$

Multiply $\frac{2}{15}$ times $\frac{7}{3}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{2\times 7}{15\times 3}$$

Do the multiplications in the fraction $\frac{2\times 7}{15\times 3}$.

$$\frac{14}{45}$$

$\frac{2 \cdot 7}{3 ^ {2} \cdot 5} = 0.3111111111111111$